Q. 164.9( 7 Votes )

Let’s solve:

i.

ii.

iii.

iv.

v.

vi.

Answer :

i. 6x = 72


Dividing both side by 6, we get


x = 12


ii. 9x + 2 = 20


9x + 2 – 2 = 20 – 2


9x = 18


Dividing both side by 9, we get


x = 2


iii. 4x – 2x + 3 = 9 – 4x


Simplifying, we get


2x + 3 = 9 – 4x


2x + 4x = 9 – 3


6x = 6


Dividing both side by 6, we get


x = 1


iv.


Taking LCM, we get



Cross Multiplying, we get


-6x = 4(21 – 2x)


-6x = 82 – 8x


8x – 6x = 82


2x = 82


Dividing both side by 2


x = 41


v. 2x – 5{7 – (x – 6) + 3x} – 28 = 39


2x – 5(7 – x + 6 + 3x) – 28 = 39


2x – 5(13 + 2x) – 28 = 39


2x – 65 – 10x – 28 = 39


2x – 10x = 39 + 28 + 65


-8x = 132


Dividing both side by -8, we get



vi.


Taking LCM,




Cross-Multiplying we get,


5(7x + 1) = 12(x + 79)


35x + 5 = 12x + 948


35x – 12x = 948 – 5


23x = 943


Dividing both side by 23, we get


x = 41


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses