Q. 165.0( 1 Vote )

Mark the correct

Answer :

Given that A = {x: –1 ≤ x ≤ 1} and f: A A such that f(x) = x |x|.


For x <0, f(x) <0


y = -x2


x = √-y, which is not possible for x > 0.


Hence, f is one-one and onto.


the given function is bijective.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Fill in theMathematics - Exemplar

Let f : [2, ∞) <sMathematics - Exemplar

Let f : N Mathematics - Exemplar

Fill in theMathematics - Exemplar

Let f :R →<Mathematics - Exemplar

Let f : [0, 1] <sMathematics - Exemplar

Which of the follMathematics - Exemplar