Answer :

From the given figure, we have

D is the mid-point of BC


Also, DE is perpendicular to AB


DF is perpendicular to AC


And, DE = DF


Now, in ∆BED and ∆CFD we have:


DE = DF


BD = CD


E = F = 90o


By RHS congruence rule


∆BED CFD


Thus, B = C


AC = AB


Hence, option (A) is correct

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