# In the given figu

From the given figure, we have

D is the mid-point of BC

Also, DE is perpendicular to AB

DF is perpendicular to AC

And, DE = DF

Now, in ∆BED and ∆CFD we have:

DE = DF

BD = CD

E = F = 90o

By RHS congruence rule

∆BED CFD

Thus, B = C

AC = AB

Hence, option (A) is correct

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