# In Fig. 4, a circ

Let AN = x cm, CM = z cm and BL = y cm

As we know that,

Tangents from an external point to a circle are equal,

In given Figure we have

AN= AM = x [Tangents from point A]

BN = BL = y [Tangents from point B]

CL = CM = z [Tangents from point C]

Now, Given: AC = 12 cm

AM + MC = 12

x + z = 12

z = 12 – x…. 

and BC = 8 cm

BL + LC = 8

y + z = 8

z = 8 – y …… 

and

AB = 10 cm

AN + BN = 10

x + y = 10 …. 

equate  and  to get,

12 – x = 8 – y

4 = x - y … 

Add  and  to get,

x + x + y – y = 10 + 4

2x = 14

x = 7 cm

put value of x in  to get,

4 = 7 – y

y = 3 cm

put value of y in  to get,

z = 8 – 3

= 5 cm

Hence,

AN = 7 cm

CM = 5 cm

BL = 3 cm

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