Q. 165.0( 1 Vote )
In a parallelogra A. 75°
B. 60°
C. 45°
D. 55°
Answer :
We know that,
The opposite angles of a parallelogram are equal
Therefore,
∠BCD = ∠BAD = 75°
Now, in ∆ BCD, we have
∠CDB + ∠DBC + ∠BCD = 180° (Since, sum of the angles of a triangle is 180o)
∠CDB + 60° + 75° = 180°
∠CDB + 135° = 180°
∠CDB = (180° - 135°) = 45°
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