Q. 164.7( 3 Votes )

In a parallelogra

Answer :

Given ,


In parallelogram ABCD,


DAB = 75°



DBC = 60°


DAB= BCD [opposite angles of parallelogram]


BCD = 75°


Now in ∆BDC


= DBC+BDC+BCD = 180°


= 60°+BDC+75° = 180°


=BDC = 180° - 135°


=BDC = 45°.

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