Q. 165.0( 4 Votes )

# If y=xsin x<

Answer :

Let u = xsin x

Taking log both sides,

log u = sin x log x

On differentiating,  Let, v = sin (xx)

Let, t = xx

log t = x log x

On differentiating,    Using (2), As, y = u + v

So, From (1) and (3), OR

y = log (1 + 2t2 + t4)

Applying the formula (a + b)2 = a2 + b2 + 2ab in (1 + 2t2 + t4).

y = log (1+t2)2

As log xn = n log x

y = 2 log (1+t2)

On differentiating, x = tan-1 t

On differentiating, Now, Again differentiating, =4(1+t2)

Therefore, Rate this question :

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