Answer :

Let AB and CD are two diameters of circle

∠AOD = ∠BOD = ∠BOC = ∠AOC = 90°

AB and CD are diagonals of quadrilateral ABCD

They intersect each other at right angles

And

AB = BC = CD = DA

We know that,

Sides of a square are equal and diagonals intersect at 90°

Therefore, ABCD is a square

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