Answer :

As 3 dice are thrown so there are 6×6×6 = 216 possibilities.


Let E denote the event of getting a total score of 5.


{(1,1,3),(1,2,2)}


As (1,1,3) can be arranged in


and (1,2,2) can be arranged in


n(E) = 6


Hence,


P(E) = 6/36 = 1/6


As our answer matches only with option (b)


Option (b) is the only correct choice.

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