Q. 165.0( 1 Vote )

# If PA and PB are two tangents to a circle with center O such that ∠AOB = 110° then ∠APB is equal toA. 55°B. 60°C. 70°D. 90°

As AP and BP are tangents to given circle,

We have,

OA AP and OB BP

[Tangents drawn at a point on circle is perpendicular to the radius through point of contact]

So, OAP = OBP = 90°

By angle sum property of quadrilateral, we have

OAP + OBP + AOB + APB = 360°

90° + 90° + 110° + APB = 360°

APB = 70°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Imp. Qs. on Circle35 mins
Quiz | Testing Your Knowledge on Circles32 mins
Short Cut Trick to Find Area of Triangle43 mins
Quiz | Imp. Qs. on Circles37 mins
Quiz | Areas Related to Circles43 mins
RD Sharma | Area of Sector and Segments25 mins
Quiz | Area Related with Circles47 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses