Q. 164.5( 2 Votes )

If 3k – 2, 4k – 6

Answer :

If three terms a1, a2 and a3 are in AP then

a3 – a2 = a2 – a1


a1 + a3 = 2a2


3k – 2 + k + 2 = 2(4k – 6)


4k = 8k – 12


4k = 12


k = 3


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