Answer :
If three terms a1, a2 and a3 are in AP then
a3 – a2 = a2 – a1
⇒ a1 + a3 = 2a2
⇒ 3k – 2 + k + 2 = 2(4k – 6)
⇒ 4k = 8k – 12
⇒ 4k = 12
⇒ k = 3
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