Answer :

Given: P (x1, y1) = (2, y1) lies on



)






Since its been given that y1 > 0 


So, y1 = 3.


P = (2, 3)


16x2 + 9y2 = 145 …… (i)


Differentiating both sides, we get,



Slope of tangent =


Slope of normal =


Equation of tangent is,


(y – 3) = (x – 2)


27y – 81 = – 32x + 64


32x + 27y - 145 = 0

Equation of normal is,


(y – 3) = (x – 2)


32y – 96 = 27x – 54


27x – 32y – 54 + 96 = 0


27x – 32y – 54 + 96 = 0


27x – 32y + 42 = 0


OR


Given: f(x) =


Differentiating w.r.t x, we get,



f(x) is strictly increasing if f'(x)>0,




f(x) is strictly decreasing if f'(x) <0


.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Show that the altMathematics - Board Papers

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1