Q. 165.0( 3 Votes )

# Find the eq

Answer :

Given: P (x1, y1) = (2, y1) lies on   )    Since its been given that y1 > 0

So, y1 = 3.

P = (2, 3)

16x2 + 9y2 = 145 …… (i)

Differentiating both sides, we get,  Slope of tangent = Slope of normal = Equation of tangent is,

(y – 3) = (x – 2)

27y – 81 = – 32x + 64

32x + 27y - 145 = 0

Equation of normal is,

(y – 3) = (x – 2)

32y – 96 = 27x – 54

27x – 32y – 54 + 96 = 0

27x – 32y – 54 + 96 = 0

27x – 32y + 42 = 0

OR

Given: f(x) = Differentiating w.r.t x, we get,  f(x) is strictly increasing if f'(x)>0,  f(x) is strictly decreasing if f'(x) <0 .

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