# <span lang="EN-US

Given that , we have to find tangent to curve which is parallel to the line 4x-2y+5=0.

Differentiating y with respect to x, we get

Now at (x1,y1) the equation will be:

The slope of the tangent at (x1,y1 ) is:

Now,

The slope of the tangent = slope of the line

Squaring both sides we get,

9 = 16(3x1 - 2)

Now,

Equation of tangent is:

y - y1 = m (x - x1)

⇒ 6(4y - 3) = 48x - 41

⇒ 24y - 18 = 48x - 41

⇒ 48x - 24y - 23 = 0

Equation of normal is:

96y - 72 = 41 - 48x

⇒48x + 96y - 113 = 0

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Find the equationRD Sharma - Volume 1

Find the equationMathematics - Board Papers

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the conditioMathematics - Exemplar