# Find: <span lang= [Applying the formula: sinθ + cos2 θ = 1]  Let sinθ = t

Differentiating both sides we get,

cosθ dθ = dt put t2 = y and do the partial fractions, 1 = A(4y + 1) + B(y + 4) = (4A + B)y + (A + 4B)

Comparing coefficients of y on both sides-

4A + B = 0 ...(1)

Also compare constant terms-

A + 4B = 1 ...(2)

On solving (1) & (2), we get-

A = -(1/15) & B = (4/15)     put t = sinθ Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Evaluate thMathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

If <img widMathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Find :

Mathematics - Board Papers

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1