Q. 165.0( 1 Vote )

By using properti

Answer :


Applying C1 C1 + C2 + C3



Taking (5x + 4) common from C1



Apply R2 R2 – R1 and R3 R3 – R1



Expanding along C1, we get


= (5x + 4)[1(4 – x)(4 – x) – 0(0)]


= (5x + 4)(4 – x)2


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