A shuttle c

Given:

Radius of lower end “r” = = 1 cm

Radius of upper end “R” = = 2.5 cm

Height of frustum “H” = 6 cm

To find: The external surface area.

Formula Used:

CSA of frustum = π(R + r)L

CSA of hemisphere = 2πr²

Explanation:

Let “L“ be the slant height of the frustum,

L of frustum =

= 6.18 cm

External Surface Area = CSA of frustum + CSA of hemisphere

= π(R + r)L + 2πr²

= π [(2.5 + 1)6.18 + 2 (1)²] cm²

= [(3.5)6.18 + 2] cm²

= [ 21.63 + 2] cm²

= (23.63) cm²

= cm²

= 74.26 cm²