Q. 15 C5.0( 2 Votes )

# Let us fill in bl

Answer :

(i) In a right angled triangle, the area of square drawn on the hypotenuse is equal to the __SUM__ of the areas of the squares drawn on the other two sides.

Explanation:

It is inferred from expression of Pythagoras theorem i.e.

H^{2} = P^{2} + B^{2}

(ii) In an isosceles right-angled triangle if the length of each of two equal sides is 42 cm, then the length of the hypotenuse will be __42√2__ cm.

Explanation:

By Pythagoras theorem we get,

h^{2} = 42^{2} + 42^{2}

⇒ h^{2} = 1764 + 1764

⇒ h^{2} = 3528

⇒ h = √3528 = 42√2 cm

(iii) In a rectangular figure ABCD, the two diagonals AC and BD intersect each other at point O, if AB = 12 cm, AO = 6.5 cm, then the length of BC is __5__ cm.

Explanation:

We know that, diagonals of a rectangle bisect each other.

So, AC = 2 × AO

⇒ AC = 2 × 6.5

⇒ AC = 13 cm

Now, applying Pythagoras theorem to ΔABC gives,

13^{2} = 12^{2} + BC^{2}

⇒ 169 = 144 + BC^{2}

⇒ BC^{2} = 169-144 = 25

⇒ BC = √25 = 5 cm

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