In the trapezium ABCD, AB || DC and AB = 7 cm and DC = 5 cm. The midpoints of AD and BC are E and F respectively, the length of EF is
A. 5 cm

B. 7 cm

C. 6 cm

D. 12 cm

In the triangle ABC, D is any point on the side AC. The midpoints of AB, BC, AD and DC are P, Q, X, Y respectively. If PX = 5 cm, then let us write the length of the side QY.

In the triangle ABC, the midpoints of AB and AC are D and E respectively; the midpoints of CD and BD are P and Q respectively. Let us prove that, BE and PQ bisect each other.

In the triangle ABC, E is the midpoint of the median AD; the extended BE intersects AC at the point F. If AC=10.5 cm, then the length of AF is

In the triangle ACB, the medians BE and CF intersects at the point G. The midpoints of BG and CG are P and Q respectively. If PQ = 3 cm, then let us write the length of BC.

In the triangle ABC, the midpoints of BC, CA and AB are D, E and F respectively; BE and DF intersect at the point X and CF and DE intersect at the point Y, the length of XY is equal to

Let us prove that, the quadrilateral formed by joining midpoints of consecutive sides of a parallelogram is a parallelogram.

D and E lie on AB and AC respectively of the triangle ABC such that, AB and Let us prove that, DE || BC and

In the triangle ABC, AD is perpendicular on the bisector of ∠ABC. From the point D, a straight line DE parallel to the side BC is drawn which intersects the side AC at the point E. Let us prove that AE = EC.

Let us prove that, the quadrilateral formed by joining midpoints of consecutive sides of a rectangular figure is not a square figure but a rhombus.