Q. 155.0( 1 Vote )

Using the propert

Answer :

To Prove:



Applying, R1 R1 – R2, we get,




Taking (a – 1) common from the first row, we get,



Now, applying R2 R2 – R3, we get,



Taking (a – 1) common from the second row, we get,



On expanding, we get,


= (a – 1)2 [(a + 1)(1 – 0) – 1(2 – 0) + 0]


= (a – 1)2 (a – 1)


= (a – 1)3 = R.H.S


Hence, Proved.


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