Answer :
(i) (102)2
This can be written as:
(100 + 2)2
Apply the identity (a+b)2 = a2 + b2 + 2ab
= (100)2 + 2 (100) (2) + 22
= 10000 + 400 + 4
= 10404
(ii) (99)2
This can be written as:
(100 – 1)2
Apply the identity (a -b)2 = a2 + b2 - 2ab
= (100)2 – 2 (100) (1) + 12
= 10000 – 200 + 1
= 9801
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Algebraic Expressions and Identities43 mins
Division of Algebraic Expressions36 mins
How to Use Algebraic Identities40 mins
Genius Quiz | Algebraic Expressions and Identities30 mins
NCERT | Practice Qs on Addition and Subtraction of Algebraic Expressions42 mins
Master Algebraic Identities43 mins
Operations on Algebraic Expressions51 mins
Algebric Expressions and Identities45 mins
Division of Algebraic Expressions37 mins
Multiplication of Algebraic Expression40 mins




















Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
State whether the
NCERT - Mathematics ExemplarFill in the blank
NCERT - Mathematics ExemplarWhat must be adde
RD Sharma - MathematicsDivide:
Divide:
Divide: