Q. 154.2( 9 Votes )

The distance between two stations is 340 Km. Two trains start simultaneously from these stations on parallel tracks and cross each other. The speed of one of the them is greater than that of the other by 5 Km/hr. If the distance between two trains after 2 hours of their start is 30 Km., find the speed of each train.

Answer :

Let, the speed of the slower train = x km/h


Speed of the faster train = (x + 5) km/h


In 2 hours slower train moved = 2x km


In 2 hours faster train moved = 2(x + 5) = (2x + 10) km


According to problem,


2x + 2x + 10 = 340 + 30


4x = 370 – 10


x = 360/9


x = 90


Speed of the slower train = x = 90 km/h


Speed of the faster train = x + 5 = 90 + 5 = 95 km/h


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