# The distance between two stations is 340 Km. Two trains start simultaneously from these stations on parallel tracks and cross each other. The speed of one of the them is greater than that of the other by 5 Km/hr. If the distance between two trains after 2 hours of their start is 30 Km., find the speed of each train.

Let, the speed of the slower train = x km/h

Speed of the faster train = (x + 5) km/h

In 2 hours slower train moved = 2x km

In 2 hours faster train moved = 2(x + 5) = (2x + 10) km

According to problem,

2x + 2x + 10 = 340 + 30

4x = 370 – 10

x = 360/9

x = 90

Speed of the slower train = x = 90 km/h

Speed of the faster train = x + 5 = 90 + 5 = 95 km/h

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Making Equations Simple41 mins
Foundation | Cracking Previous Years IMO Questions42 mins
Applications of Linear Equations in One Variable37 mins
Solution of Linear Equation34 mins
NCERT | Solving Imp. Qs. Related to Ages49 mins
Linear Equation in One Variable46 mins
Champ Quiz | Linear Equation in One Variable44 mins
Quiz | Linear Equation in One Variable48 mins
Genius Quiz | Solutions of Linear equation in One Variable26 mins
Champ Quiz | Trail of Questions on Transposition Method51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses