Answer :
Let √3-√2 be a rational number, say r
Then √3-√2=r
On squaring both sides we have
using (a-b) 2 =a 2 -2ab + b 2
Now 
is a rational number and √6 is an irrational number.
Since a rational number cannot be equal to an irrational number. Our assumption that √ 3-√2 is rational is wrong.
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