Answer :

Given, each side of square = 12cm

⇒ Area of Square ABCD = side^{2}

⇒ (12)^{2}

⇒ 144cm^{2}

Let Radius of each quadrant be r

⇒ r = 6 cm (given)

Now, the sum of the area of the four quadrants at the four corners of the square

⇒ 4 × area of each quadrant ( area of circle = πr^{2}where r is the radius)

⇒ area of quadrant =

⇒

⇒

⇒ 113.14cm^{2}

Now, area of shaded portion

= Area of square, ABCD - sum of the areas of four quadrants at the four corners of the square

⇒ 144 – 113 .14 cm^{2}

= 30 .86 cm^{2}

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