Answer :

To Prove CD<BG

Let, Center is O, Two chords are BG and CD, OM and OE are perpendicular bisector of BG and CD respectively.

In OME,

⇒ OE>OM

In OMB, Using Pythagoras Theorem

⇒ OB^{2} = OM^{2} + BM^{2} ………. (1)

In OCE

⇒ OC^{2} = OE^{2} + CE^{2} …………….. (2)

⇒ OC = OB

⇒ OM^{2} + BM^{2} = OE^{2} + CE^{2}

⇒ OE>OM

So, BM>CE

⇒ BG>CD

As Chord goes near, its length increases.

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