Answer :


To Prove CD<BG


Let, Center is O, Two chords are BG and CD, OM and OE are perpendicular bisector of BG and CD respectively.


In OME,


OE>OM


In OMB, Using Pythagoras Theorem


OB2 = OM2 + BM2 ………. (1)


In OCE


OC2 = OE2 + CE2 …………….. (2)


OC = OB


OM2 + BM2 = OE2 + CE2


OE>OM


So, BM>CE


BG>CD


As Chord goes near, its length increases.


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