Q. 155.0( 3 Votes )

# In the given figu

Radius of circle = R = 4 cm

OD perpendicular to AB is drawn

ΔABC is equilateral triangle,

A = B = C = 60°

OD/AO = sin 30°

AO = 4 cm

OD = 1/2 × 4 cm

OD = 2 cm

AD2 = OA2 – OD2

= 42 – 22 = 16 – 4 = 12 cm2

AD = 2√3 cm

AB = 2 × AD

= 2 × 2√3 cm = 4√3 cm

Area of triangle ABC = √3/4 × AB2

= √3/4 × 4√3 × 4√3

= 20.71 cm2

Area of circle = πR2

= 3.14 × 4 × 4 cm2

= 50.24 cm2

Area of shaded region = 29.53 cm2

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