Answer :

Solution:

In right angled ΔPQR,

∠ P = 90°

∠ PQR = 20°

sec θ = hypotenuse / adjacent

sec 20° = QR / PQ

1.0642 = QR / 3

QR = 1.0642 × 3

= 3.1926

QR = ST = 3.2 units

In right angled Δ ACD,

∠ CAD = 42° 6'

cot 42° 6' = AD / DC

1.1067 = AD / 1.5

∴ AD = 1.5 × 1.1067

= 1.66 units

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