Q. 155.0( 1 Vote )

# In Fig. 10.80, th

Given:

AQ = 4 cm

BR = 6 cm

PC = 5 cm

Property: If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal.

By the above property,

AR = AQ = 4 cm (tangent from A)

BR = BP = 6 cm (tangent from B)

CP = CQ = 5 cm (tangent from C)

Now,

Perimeter of ∆ABC = AB + BC + CA

Perimeter of ABC = AR + RB + BP + PC + CQ + QA

[ AB = AR + RB

BC = BP + PC

CA = CQ + QA]

Perimeter of ABC = 4 cm + 6 cm + 6 cm + 5 cm + 5 cm + 4 cm

Perimeter of ABC = 30 cm

Hence, Perimeter of ∆ABC = 30 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Area Related to Circles- Important Formula and Concepts59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 