Answer :

From the given figure, we have:

(i) In ∆ABO and ∆ACO


AB = AC (Given)


AO = AO (Common)


ABO = ACO


By SAS congruence rule



OB = OB (By CPCT)


(ii) As, By SAS congruence rule


∆ABO ACO


OAB = OAC (By Congruent parts of congruent triangles)


Hence, proved


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