Q. 154.8( 4 Votes )

In a triangle ABC, B = 50° and A = 60°. Suppose BC is extended to D. Find ACD.

Answer :


It is given that in ∆ ABC,


B = 50° and A = 60°


Here, ACD is an external angle. We know that an exterior angle of a triangle is always larger than either of the interior opposite angles.


⇒ ∠ACD = A + B = 50° + 60° = 110°


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