Q. 154.5( 6 Votes )

# In a trapezium, the length of each slant sides is 10 cm. and the length of parallel sides are 5 cm. and 17 cm. respectively. Let us write by calculating area of filed in shape of trapezium and its diagonal.

Answer :

Given, In a trapezium, the length of each slant sides is 10 cm. and the length of parallel sides are 5 cm. and 17 cm. respectively.

According to the figure two right angled triangles are formed.

In ∆AEC,

⟹ AC^{2}=AE^{2}+CE^{2} -------(i)

⟹ CE = FD

And 17 = CE +FD +EF

⟹ 17 = 2CE + 5

⟹ 2CE = 12

⟹ CE = 6cm

∴ 10^{2} = AE^{2} + 6^{2}

⟹ AE^{2}= 100 – 36

⟹ AE^{2}= 64

⟹ AE = 8cm

Hence, area of the trapezium =×(5+17)×8

= 88 sq. cm.

Rate this question :

Area of field in the shape of parallelogram ABCD is 96 sq. cm., length of diagonal BD is 12 cm. What is the perpendicular length drawn on diagonal BD from the point A?

West Bengal MathematicsLet us see the following pictures and calculate the area of its coloured part.

West Bengal Mathematics

The base of a parallelogram is twice its height. If the area of shape of parallelogram is 98 sq.cm, then let us calculate the length and height of parallelogram.

West Bengal MathematicsIf perimeter of a rhombus is 440 meter and distance between two parallel sides are 22 meter, let us write by calculating the area of shape of rhombus.

West Bengal MathematicsIn a quadrilateral ABCD, AB = 5 meter, BC = 12 meter, CD = 14 meter, DA = 15 meter and ∠ABC = 90°, let us write by calculating the area of quadrilateral shape of field.

West Bengal MathematicsIn parallelogram ABCD, AB = 4 cm., BC = 6 cm. and ∠ABC = 30°, find the area of field in the shape of parallelogram ABCD.

West Bengal MathematicsThe length of adjacent two sides are 15 cm. and 12 cm. of a parallelogram distance between two smaller sides is 7.5 cm. Then let us calculate the distance between the longer two sides.

West Bengal Mathematics