Answer :

Given, In a trapezium, the length of each slant sides is 10 cm. and the length of parallel sides are 5 cm. and 17 cm. respectively.

According to the figure two right angled triangles are formed.

In ∆AEC,

AC2=AE2+CE2 -------(i)


And 17 = CE +FD +EF

17 = 2CE + 5

2CE = 12

CE = 6cm

102 = AE2 + 62

AE2= 100 – 36

AE2= 64

AE = 8cm

Hence, area of the trapezium =×(5+17)×8

= 88 sq. cm.

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