Answer :

To prove that

y = Peax + Qebx

Differentiating with respect to x

Differentiate again

Put values of y, and in LHS

LHS= Pa2eax + Qb2ebx – (a + b)(Paeax + Qbebx) + ab(Peax + Qebx)

LHS= Pa2eax + Qb2ebx – Pa2eax – Qabebx – Pabeax – Qb2ebx + Pabeax + Qabebx

LHS = 0


Hence proved.

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