Answer :

To prove that



y = Peax + Qebx


Differentiating with respect to x



Differentiate again



Put values of y, and in LHS


LHS= Pa2eax + Qb2ebx – (a + b)(Paeax + Qbebx) + ab(Peax + Qebx)


LHS= Pa2eax + Qb2ebx – Pa2eax – Qabebx – Pabeax – Qb2ebx + Pabeax + Qabebx


LHS = 0


LHS = RHS


Hence proved.


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