Answer :

Let





We will use integration by parts for solving this integral,


Therefore,




Therefore,


3x + 5 = Ax + Bx + 6A – 3B


Comparing the coefficients, we get,


A + B = 3……(1)


6A – 3B = 5……(2)


Multiplying equation 1 by 6 and subtracting equation 2 from it, we get,


6A + 6B – 6A + 3B = 18 – 5


9B = 13



Putting the value of B in equation 1, we get,




Now,




Hence,



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