Q. 155.0( 4 Votes )

Construct each of

Answer :

Let the given right-angled triangle be ΔABC.

Steps of Construction:


(i) Draw base, BC = 3.5 cm



Now, draw a ray BX such that XBC = B = 90°.





(ii) Here, sum of two sides = AB + AC = 5.5 cm


So, cut the line segment BD = 5.5 cm from ray BX.




(iii) Join DC.




(iv)Draw perpendicular bisector of DC, say PQ, which intersects BD at A.




(v) Now join AC.




Thus, we get a ΔABC which is the required triangle.


Justification:


Base BC and B are drawn as given.


Since, PQ is perpendicular bisector of CD and A lies on it.


AD = AC


Now, AB = BD – AD


= BD – AC


AB + AC = BD


Thus, construction is justified.


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