Q. 154.3( 6 Votes )
AB and A. 55°
B. 70°
C. 110°
D. 130°
Answer :
Given that,
AB ‖ CD and PQ cuts them
EL is bisector of ∠FEB
∠LEB = ∠FEL = 35o
∠FEB = ∠LEB + ∠FEL
= 35o + 35o
= 70o
∠FEB = ∠EFC = 70o (Alternate angles)
∠EFC + ∠CFQ = 180o (Linear pair)
70o + ∠CFQ = 180o
∠CFQ = 110o
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