Q. 15

# Mark the correct alternative in the following:A 5-digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4 and 5 without repetition. The total number of ways in which this can be done isA. 216B. 600C. 240D. 3125

5-digit number divisible by 3 can be formed using 0, 1, 2, 4, 5 and 1, 2, 3, 4, 5.

When, the 5-digit number is formed using the digits 0, 1, 2, 4 and 5

So, the number of ways in which 5-digit number divisible by 3 can be formed using 0, 1, 2, 4, 5 can be done is 4×4×3×2×1

= 96.

So, the number of ways in which 5-digit number divisible by 3 can be formed using 1, 2, 4, 5 can be done is = 5P5

= 120.

The total number of ways in which 5-digit number divisible by 3 can be formed using 0, 1, 2, 3, 4, 5 can be done is = 96 + 120

= 216.

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