The length of a r

Given, The length of a rhombus is equal to length of a square and the length of diagonal of square is 10√2 cm and the length of diagonals of a rhombus are in the ratio 3 : 4

The diagonal of a square = a

10 = a

a = 10cm

i.e. the side of the square = 10 cm

according to given question side of the rhombus is equal to the side of the square

∴ side of the rhombus = 10 cm

The diagonals of a rhombus bisect each other. Let the diagonals are 3x and 4x.

Hence, 10² = (3x)² + (4x)²

⟹ 10² = 25x²

⟹ X² = 4

⟹ X = 2

∴ the diagonals are, 3x = 3×2

= 6cm

And, 4x = 4×2

= 8cm

The area of the rhombus = ×6×8

= 24 sq. cm.