Q. 144.9( 12 Votes )

The horizontal di

Answer :

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Let AB be the 1st pole and CE = 24 m be the 2nd pole


In Δ ADE,


tan 30° = DE/AD


1/√3 = DE/15


DE = 15/√3 = 5√3 = 5× 1.732 = 8.66 m


Thus, Height of the first pole = AB = CD = CE-DE = 24-8.66


= 15.34 m


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