Answer :

**Given:** Foci are (6, 4) and (-4, 4) and eccentricity is 2

**To find:** equation of the hyperbola

**Formula used:**

Standard form of the equation of hyperbola is,

Center is the mid-point of two foci.

Distance between the foci is 2ae and b^{2} = a^{2}(e^{2} – 1)

**Distance between two points (m, n) and (a, b) is given by**

**Mid-point theorem:**

Mid-point of two points (m, n) and (a, b) is given by

Center of hyperbola having foci (6, 4) and (-4, 4) is given by

= (1, 4)

Distance between the foci is 2ae and Foci are (6, 4) and (-4, 4)

{∵ e = 2}

b^{2} = a^{2}(e^{2} – 1)

Equation of hyperbola:

Hence, required equation of hyperbola is

Rate this question :

The eccentricity RD Sharma - Mathematics

The latus-rectum RD Sharma - Mathematics

The eccentricity RD Sharma - Mathematics

The foci of the hRD Sharma - Mathematics

The equation of tRD Sharma - Mathematics

The equation of tRD Sharma - Mathematics

The eccentricity RD Sharma - Mathematics

A point moves in RD Sharma - Mathematics

The equation of tRD Sharma - Mathematics

The length of theRD Sharma - Mathematics