Q. 145.0( 3 Votes )

The bisectors of exterior angles at B and C of Δ ABC meet at O, if A= x°, then BOC =
A. 90°+

B. 90°-

C. 180°+

D. 180°-

Answer :

OBC = 180o - B - (180o - B)


OBC = 90o - B


And,


OCB = 180o - C - (180o - C)


OCB = 90o - C


In


BOC + OCB + OBC = 180o


BOC + 90o - C + 90o - B = 180o


BOC = (B + C)


BOC = (180o - A) [From ]


BOC = 90o - A


BOC = 90o -

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