# Let us find the m

The data given in the question is exclusive type of data.

To find median of data, we need to make a table calculating cumulative frequency. For median:

We have, total frequency, N = 622

N/2 = 622/2 = 311

Observe, cf = 391 is just greater than 311.

Thus, median class = 60 – 70

Median is given by Where,

L = Lower class limit of median class = 60

N/2 = 311

cf = cumulative frequency of the class preceding median class = 289

f = frequency of the median class = 102

h = class interval of the median class = 10

Substituting these values in the formula of median, we get  Median = 60 + 2.157

Median = 62.157

Thus, the median of data is 62.157.

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