Q. 143.6( 15 Votes )
Let us find the m
The data given in the question is exclusive type of data.
To find median of data, we need to make a table calculating cumulative frequency.
We have, total frequency, N = 622
N/2 = 622/2 = 311
Observe, cf = 391 is just greater than 311.
Thus, median class = 60 – 70
Median is given by
L = Lower class limit of median class = 60
N/2 = 311
cf = cumulative frequency of the class preceding median class = 289
f = frequency of the median class = 102
h = class interval of the median class = 10
Substituting these values in the formula of median, we get
⇒ Median = 60 + 2.157
⇒ Median = 62.157
Thus, the median of data is 62.157.
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