Q. 143.8( 5 Votes )

In the given figu

Answer :

In ΔABC sum of all angles = 180°.

So, ∠BAC + ∠ABC + ∠ACB = 180°

30 + 50 + ∠ACB = 180

∠ACB = 100°

Since BCD represents a straight line ∠ACB + ∠ECD = 180°

So, ∠ECD = 80°

In ΔECD sum of all angles = 180°

So, ∠ECD + ∠EDC + ∠CED = 180°

60 + 40 + ∠CED = 180

∠CED = 80°

Since AEC represents a straight line, ∠CED + ∠AED = 180°

So, ∠AED = 120°

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