Answer :

In ΔABC sum of all angles = 180°.

So, BAC + ABC + ACB = 180°


30 + 50 + ACB = 180


ACB = 100°


Since BCD represents a straight line ACB + ECD = 180°


So, ECD = 80°


In ΔECD sum of all angles = 180°


So, ECD + EDC + CED = 180°


60 + 40 + CED = 180


CED = 80°


Since AEC represents a straight line, CED + AED = 180°


So, AED = 120°


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