Answer :

From the given figure, we have

AE = DB


And, CB = EF


Now, AB = (AD – DB)


= (AD – AE)


DE = (AD – AE)


Now, in ∆ABC and ∆DEF we have:


AB = DE


CB = EF


ABC = FED


By SAS congruence criterion


∆ABC DEF


Hence, option (A) is correct

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