Q. 144.1( 10 Votes )

In fig. 7, are sh

Answer :

We know that,

Tangent drawn from an external point of a circle are equal


OP = OQ = 10 cm


PQ = 5 + 5


= 10 cm


As OP = OQ = PQ


OP = OQ = OP = 10 cm


Hence, POQ is an equilateral triangle as all the sides are equal to each other


Also, angles of an equilateral triangle are of 60o


∴∠ POQ = 60o


Here, we have


Side = 10 cm


Radius, r = 5 cm


θ = 60°


And, R = 10 cm


Area of shaded region = Area of triangle OPQ + Area of semi-circle PBQM – Area of sector OPAQ





.


Hence, proved

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