Q. 145.0( 2 Votes )

In an equilateral

Answer :

Let ∆ ABC be an equilateral triangle with side a.

To prove: Area of ∆ ABC =



In ∆ ABC, AD bisects BC



Now, in ∆ ACD


Using Pythagoras theorem,


AC2 = AD2 + DC2


AD2 = AC2 – DC2




Now, in ∆ ABC


Area of ∆ ABC =


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