Answer :
To Find: Zeroes of the polynomial
Given: p(x) = 6x2 – 3 – 7x
Concept Used:
For a quadratic polynomial,
P(x) = ax2 + bx + c
Sum of the roots
The product of roots
Explanation:
P(x) = 0
6x2 – 3 – 7x = 0
6x2 – 7x – 3 = 0
(We factorized 7 such that the product is equal to 18 and the difference is equal to 7)
6x2 + 2x – 9x – 3 = 0
2x(3x + 1) – 3(3x + 1) = 0
(3x + 1)(2x – 3) = 0
Now, to verify the relationship,
Sum of the zeroes
The product of the zeroes
Hence, verified.
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