Answer :

**To Find:** Zeroes of the polynomial

**Given:** p(x) = 6x^{2} – 3 – 7x

**Concept Used:**

For a quadratic polynomial,

P(x) = ax^{2} + bx + c

Sum of the roots

The product of roots

**Explanation:**

P(x) = 0

6x^{2} – 3 – 7x = 0

6x^{2} – 7x – 3 = 0

(We factorized 7 such that the product is equal to 18 and the difference is equal to 7)

6x^{2} + 2x – 9x – 3 = 0

2x(3x + 1) – 3(3x + 1) = 0

(3x + 1)(2x – 3) = 0

Now, to verify the relationship,

Sum of the zeroes

The product of the zeroes

**Hence, verified.**

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