Find the value of

Put,

Now,

Now, for

Let,

…(1)

Consider a right angle triangle ABC, with right angle at A, as shown,

Let angle = Angle ABC

AB = base,

AC = opposite,

BC =hypotenuse

We know that,

From (1)

…(2)

Also, in a right angle triangle using, Pythogoras theorem,

(hypotenuse)² = (opposite)² + (base)²

⇒ (BC)² = (AC)² + (AB)²

From (2),

⇒(BC)² = 8AB²+AB²

⇒(BC)² = 9AB²

⇒ BC = 3AB …(3)

Now,

From (3),