# Find the value of

Put,

Now,

Now, for

Let,

…(1)

Consider a right angle triangle ABC, with right angle at A, as shown,

Let angle = Angle ABC

AB = base,

AC = opposite,

BC =hypotenuse

We know that,

From (1)

…(2)

Also, in a right angle triangle using, Pythogoras theorem,

(hypotenuse)2 = (opposite)2 + (base)2

(BC)2 = (AC)2 + (AB)2

From (2),

(BC)2 = 8AB2+AB2

(BC)2 = 9AB2

BC = 3AB …(3)

Now,

From (3),

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