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# Find the particular solution of the differential equation given that y = 0 when x = 1.**[CBSE 2014]**

**[CBSE 2014]**

Answer :

Integrate

To find the integration constant c we have given y = 0 when x = 1 hence put these (x, y) value

⇒ 0 = 2 + c

⇒ c = -2

Hence the solution will be

**The solution of the given differential equation is**

**.**

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