Answer :

(i) Assume that the given statement p is false.

So, the statement becomes the sum of an irrational number and a rational number is rational.

Let us take for example,

Where √p is irrational number and q/r and s/t are rational numbers.

Then, is a rational number and √p is an irrational number.

This is a contradiction.

∴The assumption we made is wrong.

Thus, the given statement p is true.

(ii) Assume that the given statement q is false.

So, the statement becomes if n is a real number with n > 3, then n^{2} < 9.

From the given statement, we know that n > 3 and n is a real number.

Squaring on both sides, we get

⇒ n^{2} > 3^{2}

⇒ n^{2} > 9

This is a contradiction.

∴The assumption we made is wrong.

Thus, the given statement q is true.

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