# A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non - parallel sides are 14 m and 13 m. Find the area of the field.

Given: Parallel sides of trapezium = 25 m and 10 m

Non – parallel sides of trapezium = =14 m and 13 m

To Find: Area of the field

Concept Used:

If sides of a triangle are a, b, and c, then area of a triangle is given by: Where s = semiperimeter of the triangle Diagram: Construction:

From C, draw CE || DA.

Explanation:

Now, we can see that ADCE is a parallelogram in which AE || CD and AD || CE.

Now, we can get,

AE = 10 m and CE = 13 m

BE = AB – AE [From the figure]

Therefore,

BE = 25 m – 10 m = 15 m

Now Area of trapezium = Area of Parallelogram AECD + Area of triangle ECB

Let us first calculate the area of a triangle,  s = 21 m   Area = 3 × 7 × 4 m2

Area of Δ ECB = 84 m2

We also know that Area of Δ ECB = 1/2 (BE × CL)

84 = 1/2 (15 × CL)

15 × CL = 168

CL CL = Height of the parallelogram

Now, Area of parallelogram ADCE = Base × Height

Area of parallelogram = 112 m2

Hence, Area of Trapezium ABCD = (84 + 112) m2 = 196 m2.

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