Q. 134.8( 18 Votes )

# The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Answer :

**Given:** diagonal = 24 m

p_{1} = 8 m

p_{2} = 13 m

**To find:** Area of field

**Formula Used:** Area of rhombus = 1/2 × d × (p_{1} + p_{2})

**Explanation:**

Area of quadrilateral =

Area of rhombus =

Area of rhombus =

Hence, area of quadrilateral is 252 cm^{2}

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Find the area of a rhombus, each side of which measures 20 cm and one of whose diagonals is 24 cm.

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